JEE CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

1 Easy

1 of 1

Application +4 | -1

40 milligram diatomic volatile substance

\left(X_2\right)

is converted to vapour that displaced

4.92 \mathrm{~mL}

of air at

1 \mathrm{~atm}

and

300 \mathrm{~K}

. Atomic weight of element

X

is nearly:

View answer and explanation

Correct option: D

100

Option C (200) is correct because the atomic weight of element X is calculated using the ideal gas law and the given conditions.

More Questions from SOME BASIC CONCEPTS OF CHEMISTRY

Practice All Chapter MCQs →

{H_2}O.

mol\,\,k{g^{ - 1}})

2.24 {~L}

{CH}_4

{CO}_2

0.5 \mathrm{M} \mathrm{H}_2 \mathrm{SO}_4

0.5 \mathrm{~g}

\mathrm{Cu}(\mathrm{II})