${\rm{BC}}{{\rm{l}}_3} + {{\rm{H}}_2}{\rm{O}} \to {\rm{X}},$ the products formed in the reaction are

${{\rm{H}}_3}{\rm{B}}{{\rm{O}}_3} + {\rm{HCl}}$

${{\rm{B}}_2}{{\rm{O}}_3} + {\rm{HOCl}}$

${{\rm{B}}_2}{{\rm{H}}_6} + {\rm{HCl}}$

JEE CHEMISTRY MCQ: 13 TH GROUP ELEMENTS (P-BLOCK)

1 Easy

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Understanding +4 | -1

\mathrm{BC}{\mathrm{l}_3} + {\mathrm{H}_2}\mathrm{O} \to \mathrm{X},

the products formed in the reaction are

View answer and explanation

Correct option: B

{\mathrm{H}_3}\mathrm{B}{\mathrm{O}_3} + \mathrm{HCl}

Option B (

{\mathrm{H}_3}\mathrm{B}{\mathrm{O}_3} + \mathrm{HCl}

) is correct because BCl3 reacts with water to form boric acid and hydrochloric acid.

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\mathrm{sp}^3 \mathrm{d}^2