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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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The sum ∑k=120k12k\sum\limits_{k = 1}^{20} {k\frac{1}{{{2^k}}}} is equal to
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Correct option: A
2−112192 - \frac{{11}}{{{2^{19}}}}
Option A (2−112192 - \frac{{11}}{{{2^{19}}}}) is correct because the sum of the series is found by manipulating the series and using the formula for the sum of an infinite geometric progression.

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