JEE MATHEMATICS MCQ: THEORY OF EQUATION

1 Easy

1 of 1

Application +4 | -1

\alpha ,\beta

and

\gamma

are the roots of

{x^3} + 8 = 0,

then the equation whose roots are

{\alpha ^2},{\beta ^2}

and

{\gamma ^2}

View answer and explanation

Correct option: D

{x^3} - 64 = 0

The correct answer is D (

{x^3} - 64 = 0

) because it is derived by substituting

x = \sqrt{y}

into the original equation and simplifying.

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x_1, x_2, x_3, \ldots, x_n

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