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NEET UG PHYSICS MCQ: SYSTEM OF PARTICLES

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The surface density of a circular disc of radius a depends on the distance as

\rho(r)=A+B r

. The moment of inertia about the line perpendicular to the plane of the disc is

View answer and explanation

Correct option: A

\pi a^4\left(\frac{A}{2}+\frac{2 a}{5} B\right)

Option A (

\pi a^4(\frac{A}{2}+\frac{2 a}{5} B)

) is correct because it is the result of integrating the moment of inertia over the area of the disc with the given density function.

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