JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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The sum

\frac{3 \times 1^3}{1^2}+\frac{5 \times\left(1^3+2^3\right)}{1^2+2^2}+\frac{7 \times\left(1^3+2^3+3^3\right)}{1^2+2^2+3^2}+\ldots

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Correct option: A

660

The sum of the series is 660. This is found by determining the general term of the series and then summing the first 10 terms.

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