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NEET UG PHYSICS MCQ: ELECTROMAGNETIC WAVES

1 Medium
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Application +4 | -1
An electromagnetic wave propagates in a medium, whose electric field vector is given as E=200sin⁡(18×108t+8x) V m−1E = 200\sin \left( {18 \times {{10}^8}t + 8x} \right)\,V\,{m^{ - 1}}. Refractive index of medium and amplitude of magnetic field will be
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Correct option: D
μ=43; B0=89×10−6T\mu = \frac{4}{3};\,{B_0} = \frac{8}{9} \times {10^{ - 6}}T
Option D (μ=43; B0=89×10−6T\mu = \frac{4}{3};\,{B_0} = \frac{8}{9} \times {10^{ - 6}}T) is correct because the refractive index is the ratio of the speed of light in vacuum to the speed of light in the medium, and the amplitude of the magnetic field is the amplitude of the electric field divided by the speed of light in the medium.

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