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JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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Application +4 | -1
A bulb emits light of wavelength 1987.87 nm\frac{1987.8}{7} \mathrm{~nm}. The bulb is rated as 200 W200 \mathrm{~W} and 14%14 \% of the energy is emitted as light. How many photons are emitted by the bulb per second?
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Correct option: D
4×10194 \times 10^{19}
Option D (4 × 1019) is correct because it is calculated using the formula p = (n*hc)/(t*lambda) and considering the efficiency of the bulb.

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