NEET UG PHYSICS MCQ: NUCLEI

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{U^{238}}

decays into

T{h^{234}}

by the emission of an

\alpha -

particle. There follows a chain of further radioactive decays, either by

\alpha -

decay or by

\beta -

decay. Eventually a stable nuclide is reached and after that, no further radioactive decay is possible. Which of the following stable nuclides is the end product of the

{U^{238}}

radioactive decay chain

View answer and explanation

Correct option: A

P{b^{206}}

Option A (

P{b^{206}}

) is correct because after a series of alpha and beta decays, Uranium-238 eventually transforms into Lead-206.

More Questions from NUCLEI

Practice All Chapter MCQs →

The ratio of the nuclear radii of elements with mass numbers

\mathrm{216}

and

\mathrm{125}

is In a hypothetical fission reaction

{ }_{92} X^{236} \rightarrow{ }_{56} Y^{141}+{ }_{36} Z^{92}+3 R

The identity of emitted particles

({R})

is: The radius of the nucleus of the atom with A=216 is (take

{R_0}\; = \mathrm{ }1.3fm

) The correct sequence of the increasing wavelength of the given radiation sources is Which of the following nuclear fragments corresponding to nuclear fission between neutron

\left({ }_0^1 \mathrm{n}\right)

and uranium isotope

\left({ }_{92}^{235} \mathrm{U}\right)

is correct: Which of the following has the mass closest in value to that of the positron

1\,\,a.m.u = 931\,\,MeV