JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Easy

1 of 1

Application +4 | -1

The equation of the tangent to the curve

{x^2} - 2xy + {y^2} + 2x + y - 6 = 0

at (2,2) is

View answer and explanation

Correct option: A

2x + y - 6 = 0

Option A (

2x + y - 6 = 0

) is correct because it represents the tangent line to the curve at the point (2,2) with the calculated slope.

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\mathrm{C}

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\theta = \left( {2k + 1} \right)\pi ,\;k \in Z