JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1

If the arithmetic mean of two numbers

a, b ; a>b>0

is five times their geometric mean, then

\frac{a+b}{a-b}

is equal to -

View answer and explanation

Correct option: D

\frac{5 \sqrt{6}}{12}

Option D (

\frac{{5 \sqrt{{6}}}}{{12}}

) is correct because it is the value obtained after applying componendo and dividendo twice to the given condition.

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a,b,c

a,x,b

b,y,c

{x^2},{b^2},{y^2}

P(x)=1-x+x^2-x^3+\ldots+x^{2012}

y

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y=x-2

\sum\limits_{{i=0}}^{2012} a_i

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\log \left(\frac{a}{3 b}\right)

A P

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a, b, c

\frac{3}{4}