JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

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Analyzing +4 | -1

Let

a_n

be the

n

th term of an AP. If

\sum\limits_{r = 1}^{100} {{a_{2r}}} = \alpha {\text{ and }}\sum\limits_{r = 1}^{100} {{a_{2r - 1}}} = \beta ,

the common difference of the AP is

View answer and explanation

Correct option: D

None of these

Option D (None of these) is correct. The common difference of the AP is calculated as

\frac{{\alpha - \beta}}{{100}}

, which is not among the given options.

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