JEE MATHEMATICS MCQ: SCALAR TRIPLE PRODUCT

1 Easy

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Analyzing +4 | -1

Let

O

be the origin. Let

OP = x\widehat i\mathrm{ } + y\widehat j - \widehat k

and

OQ = - \widehat i + 2\widehat j + 3x\widehat k,\,\,x,\,y \in R,\,\,x\, > \,0

be such that

|PQ| = \sqrt {20}

and the vector

OP

is perpendicular to

OQ

. If

OR = 3\widehat i + z\widehat j - 7\widehat k,\,\,z \in R

, is coplanar with

OP

and

OQ

, then the value of

{x^2} + {y^2} + {z^2}

is equal to

View answer and explanation

Correct option: B

Option B (9) is correct because by using the given conditions of perpendicularity and coplanarity, we can find the values of x, y, and z, and then calculate x² + y² + z².

More Questions from SCALAR TRIPLE PRODUCT

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\vec r\cdot\vec a = \vec r\cdot\vec b = \vec r\cdot\vec c = 0

for some non-zero vector

\vec r,

then the value of

\left[ {\vec a\vec b\vec c} \right],

is The shortest distance between the lines

\frac{{x - 3}}{2} = \frac{{y - 2}}{3} = \frac{{z - 1}}{{ - 1}}

and

\frac{{x + 3}}{2} = \frac{{y - 6}}{1} = \frac{{z - 5}}{3},

is Let

\mathbf{\vec a} = \widehat \mathbf{i} - \mathbf{\hat k},\;\mathbf{\vec b} = x\widehat \mathbf{i} + \widehat \mathbf{j} + \left( {1 - x} \right)\mathbf{\hat k}

and

\mathbf{\vec c} = y\widehat \mathbf{i} + x\widehat \mathbf{j} + \left( {1 + x - y} \right)\mathbf{\hat k}.

Then

\left[ {\mathbf{\vec a},\;\mathbf{\vec b},\;\mathbf{\vec c}} \right]

depends on If

\vec{a}, \vec{b}

are non-zero vectors, then

((\vec{a} \times \vec{b}) \times \vec{a}) \cdot((\vec{b} \times \vec{a}) \times \vec{b})

equals

a \cdot(a \times b)=

The length of the perpendicular from the origin to the plane passing through the point a and containing the line

\mathbf{r}=\mathbf{b}+\lambda \mathbf{c}