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JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1
lim⁡x→0((1−cos⁡2(3x)cos⁡3(4x))(sin⁡3(4x)(log⁡e(2x+1))5))\lim \limits_{{x \rightarrow 0}}\left(\left(\frac{1-\cos ^{2}(3 x)}{\cos ^{3}(4 x)}\right)\left(\frac{\sin ^{3}(4 x)}{\left(\log _{e}(2 x+1)\right)^{5}}\right)\right) is equal to
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Correct option: C
18
Option C (18) is correct because after applying L'Hopital's rule and trigonometric limits, the expression simplifies to 18.

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