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JEE PHYSICS MCQ: RAY OPTICS

1 Medium

1 of 1

Application +4 | -1

A lamp is hanging

1\,\,m

above the centre of a circular table of diameter

1\,\,m

. The ratio of illuminaces at the centre and the edge is

View answer and explanation

Correct option: B

{\left( {\frac{5}{3}} \right)^{\frac{3}{2}}}

Option B (

{\left( {\frac{5}{3}} \right)^{\frac{3}{2}}}

) is correct because it is the ratio of illuminances calculated using the inverse square law and the cosine of the angle of incidence.

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