JEE PHYSICS MCQ: ELECTROMAGNETIC WAVES

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Application +4 | -1

The electric field in an electromagnetic wave is given by

E = 56.5\sin \omega (t - x/c)N{C^{ - 1}}.\,

Find the intensity of the wave if it is propagating along x – axis in the free space.
(Given

{ \in _0} = 8.85 \times {10^{ - 12}}{C^2}{N^{ - 1}}{m^{ - 2}})

View answer and explanation

Correct option: B

4.24\,\,\,W{m^{ - 2}}

Option B (4.24 W/m²) is correct because the intensity of an electromagnetic wave is proportional to the square of the electric field amplitude.

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