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JEE CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

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Analyzing +4 | -1

How many species do not exist?

\begin{aligned} & {PH}_3, {PH}_5, {PCl}_5, {PBr}_5, {SiF}_6^{2-}, {SF}_6,{Al}_2{F}_6, {PbI}_4, \\ & {NCl}_5, {AlCl}_3,{OF}_2, {OH}_2, {OF}_4, {HFO}_4, {FeI}_3, {B}_2 {F}_6 \end{aligned}

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Correct option: A

Option A (8) is correct because there are 8 species among the given list that do not exist due to various chemical reasons such as exceeding the octet rule or instability.

More Questions from CHEMICAL BONDING & MOLECULAR STRUCTURE

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The hybridization in sulphur dioxide is

\mathrm{C}{\mathrm{O}_2}

has the same geometry as:

\left( A \right)\mathrm{HgC}{\mathrm{l}_2},\left( B \right)\mathrm{N}{\mathrm{O}_2},\left( C \right)\mathrm{SnC}{\mathrm{l}_4},\left( D \right){\mathrm{C}_2}{\mathrm{H}_2}

The pair of molecules forming strongest hydrogen bonds are Paramagnetism is shown by Which statement is correct? Assertion (A) :

{BF}_3

is a weaker Lewis acid than

{BCl}_3

.

Reason (R) : The planar

{BF}_3

molecule is stabilised to a greater extent than

{BCl}_3

{B}-X \pi

-bonding.