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JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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The repulsive force between two equal charges (Q)(Q) is F.F. To reduce force by 25% how much charge is transferred from first to second:-
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Correct option: C
Q2\frac{Q}{2}
Option C (Q2\frac{Q}{2}) is correct because transferring Q/2 charge results in a 25% reduction in the repulsive force between the charges.

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