The radii ${\rm{F}},{{\rm{F}}^ - },{\rm{\;O\;and\;}}{{\rm{O}}^{2 - }}$ are in the order of

${{\rm{O}}^{2 - }} > {{\rm{F}}^ - } > O > F$

${\rm{F}} > {{\rm{F}}^ - } > O > {{\rm{O}}^{2 - }}$

${{\rm{F}}^ - } > {{\rm{O}}^{2 - }} > F > O$

${\rm{F}} > O > {{\rm{F}}^ - } > {{\rm{O}}^{2 - }}$

NEET UG CHEMISTRY MCQ: CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

1 Easy

1 of 1

Understanding +4 | -1

The radii

\mathrm{F},{\mathrm{F}^ - },\mathrm{\;O\;and\;}{\mathrm{O}^{2 - }}

are in the order of

View answer and explanation

Correct option: A

{\mathrm{O}^{2 - }} > {\mathrm{F}^ - } > O > F

Option A (

{\mathrm{O}^{2 - }} > {\mathrm{F}^ - } > O > F

) is correct because negative ions are larger than their neutral atoms, and among isoelectronic species, the one with fewer protons is larger.