Dimensions of $\frac{1}{{{{\rm{\mu }}_0}{{\rm{\varepsilon }}_0}}}$, where symbols have their usual meanings, are

$\left[ {{{\rm{L}}^2}{{\rm{T}}^{ - 2}}} \right]$

$\left[ {{{\rm{L}}^{ - 1}}{\rm{T}}} \right]$

$\left[ {{{\rm{L}}^{ - 2}}{{\rm{T}}^2}} \right]$

$\left[ {{\rm{L}}{{\rm{T}}^{ - 1}}} \right]$

JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Application +4 | -1

Dimensions of

\frac{1}{{{\mathrm{\mu }_0}{\mathrm{\varepsilon }_0}}}

, where symbols have their usual meanings, are

View answer and explanation

Correct option: C

\left[ {{\mathrm{L}^2}{\mathrm{T}^{ - 2}}} \right]

Option C (

\left[ {{\mathrm{L}^2}{\mathrm{T}^{ - 2}}} \right]

) is correct because

\frac{1}{{{\mu _0}{\varepsilon _0}}}

represents the square of the speed of light, and speed has dimensions of length/time.

Practice All Chapter MCQs →

\sqrt{\frac{\text { Modulus of elasticity }}{\text { Density }}}

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\left[ {{\mathrm{M}^{ - 1}}{\mathrm{L}^{ - 3}}{\mathrm{A}^2}{T^3}} \right]

{\varepsilon _0}L\frac{{\Delta V}}{{\Delta t}},\;

{\varepsilon _0}

{\Delta V}

{\Delta t}