The electronic configuration of $\mathrm{Cu}(\mathrm{II})$ is $3 d^9$, whereas that of $\mathrm{Cu}(\mathrm{I})$ is $3 d^{10}$. Which of the following is correct?

$\mathrm{Cu}(\mathrm{II})$ is less stable

$\mathrm{Cu}$ (I) and $\mathrm{Cu}$ (II) are equally stable

Stability of $\mathrm{Cu}(\mathrm{I})$ and $\mathrm{Cu}$ (II) depends on nature of copper salts

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JEE CHEMISTRY MCQ: d & f- BLOCK ELEMENTS

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The electronic configuration of

\mathrm{Cu}(\mathrm{II})

3 d^9

, whereas that of

\mathrm{Cu}(\mathrm{I})

3 d^{10}

. Which of the following is correct?

View answer and explanation

Correct option: A

\mathrm{Cu}

(II) is more stable

Option A (Cu(II) is more stable) is correct because although Cu(I) has a stable

3d^{10}

configuration, Cu(II) is more stable in aqueous solution due to its higher hydration energy which compensates for the energy needed for the second ionization.

JEE CHEMISTRY MCQ: d & f- BLOCK ELEMENTS

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