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JEE CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

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Choose the correct option based on following statements. Here ‘T’ stands for true and ‘F’ stands for false statement.
(i) Molecular mass of cane sugar (C12H22O11)(C_{12}H_{22}O_{11}) is 182 amu.
(ii) 1 mole of cane sugar contains 6.022×10236.022 \times 10^{23} molecules of cane sugar.
(iii) 34.20 g of cane sugar contains 6.022×10216.022 \times 10^{21} molecules of cane sugar.
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Correct option: C
FTF
Option C (FTF) is correct because the molecular mass of cane sugar is 342 amu, 1 mole contains 6.022 × 1023 molecules, and 34.20 g contains 6.022 × 1022 molecules.

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