NEET UG CHEMISTRY MCQ: P-BLOCK ELEMENTS

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Application +4 | -1

\text{XeF}_{4}

reacts with

\mathrm{SbF}_{5}

to form

\left[\mathrm{XeF}_{\text{m}}\right]^{\text{n}+}\left[\mathrm{SbF}_{\text{y}}\right]^{2-}

\mathrm{m}+\mathrm{n}+\mathrm{y}+\mathrm{z}=\text {? }

View answer and explanation

Correct option: A

Option A (11) is correct because the reaction forms

[XeF_3^+][SbF_6^-]

, so m=3, n=1, y=6, and z=1, thus m+n+y+z = 3+1+6+1 = 11.

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