JEE MATHEMATICS MCQ: INCREASING & DECREASING

1 Easy

1 of 1

Application +4 | -1

The interval of increase of the function

F\left( x \right) = x - {e^x} + \tan \left( {\frac{{2\pi }}{7}} \right)

View answer and explanation

Correct option: B

\left( { - \infty ,\;0} \right)

Option B (

\frac{\pi }{2}

) is correct because it is the value of c within the given interval that satisfies Lagrange's Mean Value Theorem.

More Questions from INCREASING & DECREASING

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f\left( x \right) = \frac{{K\sin x + 2\cos x}}{{\sin x + \cos x}}

x

f\left( x \right) = {x^2} + ax + 1

a

f(x)=

\sin x-\cos x-a x+b

f(x)=x e^{x(1-x)}, x \in R

f

g

fog

f\left( x \right) = {x^3} + b{x^2} + cx + d

0 < {b^2} < c

\left( { - \infty ,\;\infty } \right)