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JEE PHYSICS MCQ: WAVE OPTICS

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Application +4 | -1

In a Young’s experiment, two coherent sources are placed

0.90\;mm

apart and the fringes are observed one meter away. If it produces the second dark fringe at a distance of

1\;mm

from the central fringe, the wavelength of monochromatic light used will be

View answer and explanation

Correct option: D

6 \times {10^{ - 5}}\;\mathrm{cm}

Option D (

6 \times {10^{ - 5}}\;\mathrm{cm}

) is correct because it is the wavelength calculated using the formula for the position of dark fringes in Young's experiment.

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