JEE MATHEMATICS MCQ: SYSTEM OF CIRCLES

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If the circle

x^2+y^2+2 g x+2 f y+c=0

bisects the circumference of the circle

x^2+y^2+2 g^{\prime} x+2 f^{\prime} y+c^{\prime}=0

, then the length of the common chord of these two circles, is

View answer and explanation

Correct option: B

2 \sqrt{g^{\prime 2}+f^{\prime 2}-c^{\prime}}

Option B (

2 \sqrt{g^{\prime 2}+f^{\prime 2}-c^{\prime}}

) is correct because when one circle bisects the circumference of another, the common chord is the diameter of the bisected circle.

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