NEET UG CHEMISTRY MCQ: Equilibrium

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Which of the following relation represents correct relation between standard electrode potential and equilibrium constant?

I.

\log {K}=\frac{{nFE}^{\circ}}{2.303 {RT}}

II.

{K}={e}^{\frac{{nFE}^{\circ}}{{RT}}}

III.

\log {K}=\frac{-{nFE}^{\circ}}{2.303 {RT}}

IV.

\log {K}=0.4342 \frac{-{nFE}^{\circ}}{{RT}}

Choose the correct statement(s).

View answer and explanation

Correct option: C

I, II and IV are correct

Option C is correct because relations I, II, and IV correctly represent the relationship between standard electrode potential and equilibrium constant.

More Questions from Equilibrium

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Given below are two statements: One is labelled as Assertion A and the other labelled as Reason R.
Assertion A: During the boiling of water having temporary hardness,

Mg{(HC{O_3})_2}

is converted to

MgC{O_3}

.
Reason R The solubility product of

Mg{(OH)_2}

is greater than that of

MgC{O_3}

.
In the light of the above statements, choose the most appropriate answer from the options given below At a certain temperature,

K_{\mathrm{P}}

for the dissociation of solid

\mathrm{CaCO}_3

4.5 \times 10^{-2}

atm and for the reaction

\mathrm{C}(\mathrm{s})+\mathrm{CO}_2(\mathrm{g}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g}),

the

K_{\mathrm{P}}

value is

2.0 \mathrm{~atm}.

The pressure of carbon monoxide at this temperature, when solid carbon

\mathrm{CaO}

and

\mathrm{CaCO}_3

are mixed together and allowed to attain equilibrium is Phenolphthalein shows … in acid medium. At the state of dynamic equilibrium, for solute

+

solvent

\leftrightharpoons

solution. For

\mathrm{PC}{\mathrm{l}_5}\leftrightharpoons\mathrm{PC}{\mathrm{l}_3} + \mathrm{C}{\mathrm{l}_2}

, initial concentration of each reactant and product is 1 M. If

{K_{\mathrm{eq}}} = 0.41

then Select the

\mathrm{p}{K_a}

value of the strongest acid from the following