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JEE PHYSICS MCQ: OSCILLATIONS

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A simple harmonic wave having an amplitude a and time period T is represented by the equation y=5sin⁡π(t+4)my = 5\sin \pi \left( {t + 4} \right)m then the value of amplitude (a) in (m) and time period (T) in second are
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Correct option: D
a = 5, T = 2
Option D is correct because by comparing the given equation to the standard form, we can identify the amplitude as 5 and the time period as 2.

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