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JEE MATHEMATICS MCQ: LIMITS

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Ltx→1 [[4x2−x−1−1−3x+x21−x3]−1+3(x4−1)x3−x−1]=\underset{x\to 1}{\mathop{Lt}}\,\left[ {{\left[ \frac{4}{{{x}^{2}}-{{x}^{-1}}}-\frac{1-3x+{{x}^{2}}}{1-{{x}^{3}}} \right]}^{-1}}+\frac{3\left( {{x}^{4}}-1 \right)}{{{x}^{3}}-{{x}^{-1}}} \right]=
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Correct option: B
3
Option B (3) is correct because after simplification and applying the limit, the expression evaluates to 3.

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