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JEE MATHEMATICS MCQ: PERMUTATIONS

1 Easy

1 of 1

Application +4 | -1

If

\frac{1}{6 !}+\frac{1}{7 !}=\frac{x}{8 !}

, then the value of

x=2^m

. The value of

m

is

View answer and explanation

Correct option: A

6

Option A (6) is correct because simplifying the equation

\frac{1}{6 !}+\frac{1}{7 !}=\frac{x}{8 !}

leads to

x=64

, which is

2^6

.

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