JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1

s

is the sum of an infinite GP and the first term is

a

, then the common ratio

r

given by

View answer and explanation

Correct option: B

\frac{s-a}{s}

Option B (

\frac{s-a}{s}

) is correct because it is derived directly from the formula for the sum of an infinite geometric progression.

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A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}

{A} \cup({B} \cap {C})

A-(B \cap C)

(B \cup C)-A

a,b,c

a,x,b

b,y,c

{x^2},{b^2},{y^2}

P(x)=1-x+x^2-x^3+\ldots+x^{2012}

y

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y=x-2

\sum\limits_{{i=0}}^{2012} a_i

\log \left(\frac{5 c}{a}\right), \log \left(\frac{3 b}{5 c}\right)

\log \left(\frac{a}{3 b}\right)

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G P

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\frac{3}{4}