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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1
Let 1x1,1x2,1x3,….,(xi≠0\frac{1}{x_{1}}, \frac{1}{x_{2}}, \frac{1}{x_{3}}, \ldots .,\left(x_{i} \neq 0\right. for i=1,2,…,n)\left.i=1,2, \ldots, n\right) be in A.P. such that x1=4x_{1}=4 and x21=20x_{21}=20. If nn is the least positive integer for which xn>50x_{n}>50, then ∑i=1n(1xi)\sum_{i=1}^{n}\left(\frac{1}{x_{i}}\right) is equal to.
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Correct option: C
134\frac{13}{4}
Option C (13/4) is correct because it is the sum of the reciprocals of the first n terms of the A.P., where n is the least positive integer for which x_n > 50.

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