JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Hard

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Analyzing +4 | -1

The value of

\sum\limits_{{n=1}}^{\infty} \frac{\tan \left(\frac{\theta}{2^n}\right)}{2^{n-1} \cos \left(\frac{\theta}{2^{n-1}}\right)}

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Correct option: A

\frac{2}{\sin 2 \theta}-\frac{1}{\theta}

Option A (

\frac{{2}}{{\sin 2 \theta}} - \frac{{1}}{{\theta}}

) is correct because the infinite sum telescopes and simplifies to this expression.

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