JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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\frac{1}{{{3^2} - 1}} + \frac{1}{{{5^2} - 1}} + \frac{1}{{{7^2} - 1}} + .... + \frac{1}{{{{(201)}^2} - 1}}

is equal to

View answer and explanation

Correct option: B

\frac{{25}}{{101}}

Option B (25/101) is correct because the sum can be expressed as a telescoping series and simplified.

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