NEET UG PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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The Gaussian surface for calculating the electric field due to a charge distribution is

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Correct option: C

A symmetrical closed surface containing the charge distribution, at every point of which electric field has a single fixed value

Option A symmetrical closed surface containing the charge distribution, at every point of which electric field has a single fixed value is the correct answer because it accurately describes the requirements for a Gaussian surface.

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The ratio of magnitude of electric displacement (D) and electric field (E) is Gauss’s Law is valid for In hydrogen like system the ratio of coulombian force and gravitational force between an electron and a proton is in the order of: Statement-1:

\overrightarrow{{E}}

in outside velocity of a conductor depends only on the local charge density

\alpha

.
Statement-2:

\overrightarrow{{E}}

in outside vicinity of a conductor is given by

\frac{\sigma}{\varepsilon_0}

. Two charges each of 1 coulomb are at a distance 1

km

apart the force between them is

P \times 10^3

then value of

{P}

is Electric field due to point charge depends on distance

r