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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Medium
1 of 1
Application +4 | -1
1⋅1!+2⋅2!+3⋅3!+…+n⋅n!=1 \cdot 1 !+2 \cdot 2 !+3 \cdot 3 !+\ldots+n \cdot n !=
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Correct option: B
(n+1)!−1(n+1) !-1
Option B ((n+1)!−1(n+1)! - 1) is correct because the series can be simplified by expressing each term as a difference of factorials.

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