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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Sum of the series 11!50!+13!48!+15!46!+⋯+15!0!\frac{1}{1 ! 50 !}+\frac{1}{3 ! 48 !}+\frac{1}{5 ! 46 !}+\cdots+\frac{1}{5 ! 0 !} is:
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Correct option: D
25051!\frac{2^{50}}{51 !}
Option D (25051!\frac{2^{50}}{51 !}) is correct because the sum of the series can be expressed as a binomial coefficient sum, which simplifies to 25051!\frac{2^{50}}{51 !}.

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