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JEE PHYSICS MCQ: CURRENT ELECTRICITY

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A cathode emits 1.8×10141.8 \times {10^{14}} electrons per second. When heated when 400 V is applied to anode all the emitted electrons reach the anode. The charge on electron is 1.6×10−19C1.6 \times {10^{ - 19}}C. The maximum anode current is
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Correct option: B
29 μA29\,\mu A
Option B (29 μA29\,\mu A) is correct because the current is calculated by multiplying the number of electrons emitted per second by the charge of an electron.

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