JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1

[x]

denotes the greatest integer less than or equal to

x

, then,

\lim \limits_{{n \rightarrow \infty}} \frac{\left[1^2 x\right]+\left[2^2 x\right]+\left[3^2 x\right]+\ldots . .+\left[n^2 x\right]}{n^3}

equals

View answer and explanation

Correct option: B

x / 3

Option B (

x / 3

) is correct because the limit is evaluated using the Squeeze Theorem and the sum of squares formula.

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