JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

1 Hard

1 of 1

Application +4 | -1

The magnitude of the average electric field normally present in the atmosphere just above the surface of the earth is about

150\,N/C,

directed inward towards the center of the earth. This gives the total net surface charge carried by the earth to be:

\left[ {{\text{Given}}\,{\varepsilon _0} = 8.85 \times {{10}^{ - 12}}\,{C^2}/N - {m^2},\,{R_E} = 6.37 \times {{10}^6}\,m} \right]

View answer and explanation

Correct option: C

- 680\,kC

Option C (

- 680\,kC

) is correct because the total net surface charge is calculated using Gauss's law and the given electric field, directed inward.

More Questions from ELECTRIC FIELDS AND CHARGES

Practice All Chapter MCQs →

r.

4N

\left( {{\varepsilon _r} = 8} \right)

N

5 \times {10^{ - 2}}