JEE CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

1 Medium

1 of 1

Analyzing +4 | -1

S - O,\,\,B - O\,\,

and

P - O

bond order in

P{O_4}^{ - 3},S{O_4}^{ - 2}

and

B{O_3}^{3 - }

ions fallows the order.

View answer and explanation

Correct option: C

S{O_4}^{ - 2} > P{O_4}^{ - 3} > B{O_3}^{ - 3}

Option C (

S{O_4}^{ - 2} > P{O_4}^{ - 3} > B{O_3}^{ - 3}

) is correct because the bond order is determined by the number of resonance structures, with sulfate having the highest and borate the lowest.

More Questions from CHEMICAL BONDING & MOLECULAR STRUCTURE

Practice All Chapter MCQs →

\mathrm{C}{\mathrm{O}_2}

\left( A \right)\mathrm{HgC}{\mathrm{l}_2},\left( B \right)\mathrm{N}{\mathrm{O}_2},\left( C \right)\mathrm{SnC}{\mathrm{l}_4},\left( D \right){\mathrm{C}_2}{\mathrm{H}_2}

{BF}_3

{BCl}_3

{BF}_3

{BCl}_3

{B}-X \pi