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NEET UG PHYSICS MCQ: WAVE OPTICS

1 Medium
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Application +4 | -1
Critical angle for certain medium is sin⁡−1(0.6).{\sin ^{ - 1}}\left( {0.6} \right). The polarizing angle of that medium is
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Correct option: C
tan⁡−1[1.6667]{\tan ^{ - 1}}\left[ {1.6667} \right]
The correct answer is C (tan⁡−1[1.6667]{\tan ^{ - 1}}\left[ {1.6667} \right]) because it is the Brewster's angle calculated from the refractive index, which is derived from the critical angle.

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