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JEE MATHEMATICS MCQ: PERMUTATIONS

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Analyzing +4 | -1
Let E=[13+150]+[13+250]+[13+350]+…+50 terms,E=\left[\frac{1}{3}+\frac{1}{50}\right]+\left[\frac{1}{3}+\frac{2}{50}\right]+\left[\frac{1}{3}+\frac{3}{50}\right]+\ldots+50 \text { terms,} then the exponent of 2 in EE! is
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Correct option: C
15
The correct answer is C (15) because after evaluating the sum E to be 17, the exponent of 2 in 17! is calculated using Legendre's formula.

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