JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

1 Easy

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Application +4 | -1

The value of the constant '

m

' and '

c

' for which

y=m x+c

is a solution of the differential equation

D^2 y-3 D y-4 y=-4 x

View answer and explanation

Correct option: B

m=1 ; c=-3 / 4

Option B (m=1 ; c=-3 / 4) is correct because substituting these values into the differential equation satisfies the given condition.

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y=y(x)

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x = A\cos 4t + B\sin 4t,

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y=y(t)

\frac{d y}{d t}+\alpha y=\gamma e^{-\beta t}

\alpha>0, \beta>0

\gamma>0

\lim \limits_{{x \rightarrow \infty}} y(t)