NEET UG CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

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Analyzing +4 | -1

Which does not use

s{p^3}

-hybrid orbitals in its bonding?

View answer and explanation

Correct option: A

\mathrm{BeF}_3^ -

Option A (

\mathrm{BeF}_3^ -

) is correct because Be in

\mathrm{BeF}_3^ -

sp^2

hybridized, while the others are

sp^3

hybridized.

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