JEE MATHEMATICS MCQ: ELLIPSE

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Analyzing +4 | -1

From a point P, perpendicular tangents

P Q

and

P R

are drawn to ellipse

x^2+4 y^2=4

. The locus of the circumcentre of

\Delta P Q R

, is

View answer and explanation

Correct option: B

x^2+y^2=\frac{5}{16}\left(x^2+4 y^2\right)^2

Option B (

\frac{1}{\sqrt{1+\sin ^2 \theta}}

) is correct because it represents the eccentricity of the ellipse when the chord QR subtends a right angle at the center C.

More Questions from ELLIPSE

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\frac{x^2}{144}+\frac{y^2}{81}=1

m

\mathrm{M}

\mathrm{mM}

P

\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{{16}} = 1

S

S'.

A

PSS',

A

A

B

(\sqrt{7}, 0)

(-\sqrt{7}, 0)

P

9 x^{2}+16 y^{2}=144

\mathrm{PA}+\mathrm{PB}

\frac{x^2}{a^2}+\frac{y^2}{b^2}=1

r

\frac{x^2}{25}+\frac{y^2}{16}=1

P

x=0

Q

R

Q

y=x

Q

R

N P

Q

P

O