Question

The magnetic field in a plane electromagnetic wave is given by

B=(200 \mu \mathrm{T}) \sin \left[\left(4.0 \times 10^{15} \mathrm{~s}^{-1}\right)(t-x / c)\right] .

Find the maximum electric field and the average energy density corresponding to the electric field.

Accepted Answer

$6 	imes 10^4 \mathrm{~N} \mathrm{~C}^{-1}, 0.016 \mathrm{~J} \mathrm{~m}^{-3}$

Answer

$6 	imes 10^4 \mathrm{~N} \mathrm{~C}^{-1}, 1.106 \mathrm{~J} \mathrm{~m}^{-3}$

Answer

$3 	imes 10^4 \mathrm{~N} \mathrm{~C}^{-1}, 0.016 \mathrm{~J} \mathrm{~m}^{-3}$

Answer

$6 	imes 10^{14} \mathrm{~N} \mathrm{~C}^{-1}, 6.101 \mathrm{~J} \mathrm{~m}^{-3}$

JEE PHYSICS MCQ: ELECTROMAGNETIC WAVES

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