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JEE PHYSICS MCQ: ELECTROMAGNETIC WAVES

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Application +4 | -1

An EM wave is given by

\mathrm{E}=200 \sin \left[1.5 \times 10^7 \mathrm{t}-0.05 \mathrm{x}\right] \mathrm{N} / \mathrm{C}

Find the intensity of wave.

\left[\varepsilon_0=8.85 \times 10^{-12}\right.

SI units

]

View answer and explanation

Correct option: A

53.1

Option A (53.1) is correct because the intensity of the wave is calculated using

I = \frac{1}{2} \varepsilon_0 E_0^2 c

.

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