In the reaction sequence, the product $Y$ is ${C_6}{H_6}\xrightarrow[{AlC{l_3}}]{{C{H_3}Cl}}X\xrightarrow{{KMn{O_4}}}Y$

NEET UG CHEMISTRY MCQ: HYDROCARBONS

1 Medium

1 of 1

Application +4 | -1

In the reaction sequence, the product

Y

{C_6}{H_6}\xrightarrow[{AlC{l_3}}]{{C{H_3}Cl}}X\xrightarrow{{KMn{O_4}}}Y

View answer and explanation

Correct option: C

benzoic acid

Option A is correct because the reaction requires deprotonation of both acidic hydrogens of ethyne using

NaNH_2

, followed by alkylation with excess ethyl iodide to form Hex-3-yne.