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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy
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Application +4 | -1
If ω\omega is a complex cube root of unity, then for positive integral value of nn, the product of ω.  ω2.  ω3…  ωn\omega .\;{\omega ^2}.\;{\omega ^3} \ldots \;{\omega ^n} will be
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Correct option: D
Both (2) and (3)
Option D (Both (2) and (3)) is correct because the product simplifies to ωn(n+1)2\omega^{\frac{{n(n+1)}}{{2}}}, which can be either 1 or ω\omega depending on the value of n.

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